Term and formula assignment
In a previous card, it was described how an \( \mathcal{L} \)-structure and a variable assignment fuction act together to identify a set theoretic interpretation for every symbol of a language. For terms and formulas, they have an interpretation assigned to them by a term assignment function and a formula assignment function. Terms get assigned to elements while (some) formulas get assigned "truth" (also called "satisfaction").
Term assignment function
Let \( \mathcal{L} \) be a language, and let \( \mathfrak{U} \) be an \( \mathcal{L} \)-structure for the language. Let \( A \) be the universe of \( \mathfrak{U} \) and let \( s \) be a variable assignment function.
The term assignment function, denoted \( \bar{s} \), is a mapping of terms to elements of \( A \). It is defined recursively and is fully determined by the combination of the \( \mathcal{L} \)-structure and the variable assignment function.
Let \( t \) be a term, then:
- if \( t \) is a variable symbol, [\( \bar{s}(t) = \, ? \, \)]
- if \( t \) is a constant symbol \( c \), [\( \bar{s}(t) = \, ? \, \)]
- if \( t \) is \( ft_1t_2...t_n \) for some function and term symbols, then [\( \bar{s}(t) = f^{ \mathfrak{U} }(\, ? \, ) \) ]
Formulas get a very different mapping.
Formula assignment: truth/satisfaction
Let \( \mathcal{L} \) be a language, and let \( \mathfrak{U} \) be an \( \mathcal{L} \)-structure for the language. Let \( A \) be the universe of \( \mathfrak{U} \) and let \( s \) be a variable assignment function (and \( \bar{s} \) the resulting term assignment function).
Let \( \phi \) be a formula valid in \( \mathcal{L} \). We say that \( \phi \) is true in \( \mathfrak{U} \), or that \( \mathfrak{U} \) satisfies \( \phi \), and we write \( \mathfrak{U} \vDash \phi \), iff one of the following conditions holds:
- \( \phi :\equiv Rt_1t_2...t_n \) and [\( \, ? \, \in \, ? \, \)].
- \( \phi :\equiv (\alpha \lor \beta) \) and [condition 1] or [condition 2].
- \( \phi :\equiv \forall x \; (\alpha) \) and for each element \( a \in A, \; \mathfrak{U} \vDash \alpha[s(x|a)] \; \).
- \( \phi :\lnot (\alpha) \) and \( \mathfrak{U} \nvDash \alpha[s] \).
\( \mathfrak{U} \nvDash \phi \) means it's not the case that \( \mathfrak{U} \vDash \phi \).
There is a discussion about the meaning of \( \nvDash \) on the back side.